If you are good at math...

Looking for someone who could possible tutor me in math on skype or something...please. I am in Alg. 2 and if I don't pass this year (I'm a senior in HS) I can't graduate...

What is the equation, in standard form, of a parabola that contains the following points? (−2, 18), (0, 4), (4, 24) Solve by using tables. Give each answer to at most two decimal places. x2 − 5x + 6 = 0 etc...a lot of them are pictures of graphs etc...I am not very smart at math.

Alot of us aren't very good at math myself included, so don't feel alone K? ;) Anyway I wished I could help but my brain just overheated on trying to understand it.

(−2, 18), (0, 4), (4, 24) okay we got this three points, a parabola in a function works the following always: -------(Y = ax^2 + bx + c)-------- There has to be a way for the value X and Y in the point (0,4), 0=x and 4=Y With that in mind we can have the following substitution on the parabola We would have the following result -------(4 = a(0)^2 + b(0) + c)------ by answering this the result would be : ~~(4=C)~~ With this now we need the values of A and B now lets get the next point: (-2,18) by the substitution like last time we would get: ------(18 = a(-2)^2 + b(-2) + c)------ this would mean that our result would be the following: -----(18 = 4a -2b + c)---- but lets remember we got C last time, so now it would become ------(18=4a-2b+4)----- We send the value of 4 to next side, since its +4 it would become -4 18-4=4a-2b meaning we would end in ---(14=4a-2b)---- so far we got two * 4=C * 14= 4a-2b now lets go for the last point (4,24) by substitution we would get 24 = a(4)^2 + b(4) + c by simplificating again we would get 24 = 16a + 4b + 4, since we already knew the value of C so in the end we would end up with ----(20 = 16a + 4b)----- now we got two equations we can solve by system 14= 4a-2b and 20= 16a+4b by system we can find lots of ways to know "A" and "B" I prefer this method (4a-2b=14)(2) we do this to eliminate the B 16a+4b=20 ------------ 24a=48 would mean to get A=48/24 A=2 so now we can get b by simple substitution 4(2)-2B=14 -2B=14-8 B=6/-2 B=-3 so our final result for the equation of the parabola in standard form would be : (Y = 2x^2 -3x + 4) in wich A=2, B=-3 and C=4 well thats how you solve that one hope it helped you a bit